The formula for determining the frequency, f, of a note on a piano is f=440(2)^h/12 where h is the number of half-steps from the a above middle c on the keyboard. a note is six half-steps away from the a above middle c. the frequency of the a above middle c is 440 hz. how much greater is the frequency of the new note compared with the frequency of the a above middle c?
a)29.3%
b)41.4%
c)70.7%
d)182.3%

41.4%

Step-by-step explanation:

The formula for determining the frequency:  --A

where h is the number of half-steps from the A above middle C on the keyboard.

A note is six half-steps away from the A above middle C.

Now we are supposed to find How much greater is the frequency of the new note compared with the frequency of the A above middle C?

Now initially there is no half steps .

So, substitute h =0

Now we are given that A note is six half-steps away from the A above middle C

So, substitute h =6

Now To find change percentage

Formula:

Hence  the frequency of the new note is 41.4% greater with the frequency of the A above middle C.

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.