Problem situation: anna is at the movie theater and has $35 to spend. she spends $9.50 on a ticket and wants to buy some snacks. each snack costs $3.50. how many snacks, x, can anna buy? inequality that represents this situation: 9.50+3.50x? 35 drag each number to show if it is a solution to both the inequality and the problem situation, to the inequality only, or if it is not a solution. 4 314 912 4.25 ? 2 2 solution to both the inequality and the situation solution to the inequality only not a solution

The answer in the procedure

Step-by-step explanation:

Let

x-----> the number of snacks

we  know that

The inequality that represent this situation is

Solve for x

The maximum number of snacks is 7

The solution for the inequality is all real numbers less than or equal to 7.3 snacks

The solution for the problem situation is all whole positive numbers less than or equal to 7 snacks

Verify each case

case 1) 4 snacks

Is a solution to both the inequality and the problem situation

case 2) 314 snacks

Is not a solution

case 3) 912 snacks

Is not a solution

case 4) 4.25 snacks

Solution to the inequality ONLY

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all

add the numbers under frequency to find the total number:

5 + 8 +7 + 4 + 0 +1 = 25

the answer is 25.