Question 1
24/6 yields 4 while 54/6 yields 9. every other combination of numbers will yield at least one result with a quotient and remainder.
Question 2
8 is the only number that is a common factor of 24, 48 and 144
Question 3
- (y^4)^2 = y^(4*2) = y^8
- (y^5)^2 = y^(5*2) = y^10
- (y^10)^2 = y^(10*2) = y^20 (correct answer)
- (y^12)^2 = y^(12*2) = y^24
Question 4
64^8 = 2^48
- (8^4)^2 = (8^8) = (2^3)^8 = (2^24)
- (32^4)^2 = (32^8) = (2^5)^8 = (2^40)
- (32^8)^2 = (32^16) = (2^5)^16 = (2^80)
- (8^8)^2 = (8^16) = (2^3)^16 = (2^48) (correct answer)
Question 5
4 * 12 = 48
-2 * -24 = 48
-8 * 6 = -48 (correct answer)
6 * 8 = 48
Question 6
131 is the only prime number
Question 7
104 = 2 * 2 * 2 * 13 = 2^3 * 13
Question 8
476 = 2 * 2 * 7 * 17 = 2^2 * 7 * 17
Question 9
104 = 2 * 2 * 2 * 13
260 = 2 * 2 * 5 * 13
Greatest common factor = 2 * 2 * 13 = 52
Question 10
312 = 2 * 2 * 3 * 13
444 = 2 * 2 * 3 * 37
Greatest common factor = 2 * 2 * 3 = 12
Question 11
a^6/a^2 = a^4 i.e. a to the power of 4
Question 12
Power of a Power Property
Question 13
(h/5)^2 = (h^2)/(5^2) = (h^2)/25
fraction numerator h squared over denominator 25 end fraction
Question 14
(3* m^2 * n^4)^3 = 3^3 * m^2*3 * n^4*3 = 27 * m^6 * n^12
27 m to the power of 6 end exponent n to the power of 12
Question 15
(3y)^4 * y^(-2) = 3 * y^(4-2) = 3y^2
3 y squared
Question 16 is missing
Question 17
(4 * x^8) / (16 * x^2) = x^(8-2) / 4 = (x^6)/4