Solve using the elimination method -4x+2y=8 4x+4y=28

x = -1

y = 6

Step-by-step explanation:

Equation (1) : -4x + 2y = 8

Equation (2) : 4x + 4y = 28

(1) + (2):

6y = 36

y = 6

Sub y = 6 into (1):

-4x + 2(6) = 8

-4x + 12 = 8

-4x = -4

x = -1

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.

3,6 and 7.

step-by-step explanation:

a) unit place of 37 is 7

so the unit place of cube of 37 will be

7³= 343=3

the answer is 3.

b) unit place of 56 is 6, so the unit place of cube of 56 will be

6³= 216=6

the answer is 6.

c) unit place of 133 is 3, so the unit place of cube of 133 will be

3³= 27= 7.

the answer is 7.