At a local company, the ages of all new employees hired during the last 10 years are normally distributed. the mean age is 38 years old, with a standard deviation of 10 years. find the percent of new employees that are no more than 30 years old. round to the nearest percent.

P = 21%

Step-by-step explanation:

We look for the percentage of employees who are not more than 30 years old.

This is:

Where x is the number of new employees who are not over 30 years old and n is the total number of new employees.

We do not know the value of x or n. However, the probability of randomly selecting an employee that is not more than 30 years old is equal to

Then we can solve this problem by looking for the probability that a new employee is not more than 30 years old.

This is:

Then we find the z-score

We know that:

μ = 38 years

years

So

Then

By symmetry of the distribution

Looking in the normal standard tables

Finally P = 21%

687.09 dollars       happy now

step-by-step explanation: 6870

1857 times .63 equals 1169.91 subtract that from 1857 you get 687.09

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this