What is sin a, sin b, cos a, cos b, tan a, tan b?

Sin A=12/13 Sin B=5/13 Cos A=5/13 Cos B=12/13 Tan A=12/13 Tan B= 5/13

Step-by-step explanation:

I memory trick people use in Soh Cah Toa where for sin, the two numbers you use for the fraction are Opposite/Hypotenuse (sOH), tan is Opposite/Adjacent (tOA) cos is Adjacent/Hypotenuse (cAH). so...

Sin A=12/13 (Opposite/Hypotenuse)

Sin B=5/13 (Opposite/Hypotenuse)

Cos A=5/13 (Adjacent/Hypotenuse)

Cos B=12/13 (Adjacent/Hypotenuse)

Tan A=12/13 (Opposite/Adjacent )

Tan B= 5/13 (Opposite/Adjacent )

Hope this helps.

Have a great day

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value