Mathematics, 03.02.2020 00:59 10121545

to practice writing the equations of horizontal parabolas, write the equations of these two parabolas in vertex form:

focus at (4, 3), and directrix x = 2
focus at (2, -1), and directrix x = 8

Answers: 1

Show answers

Answers

Answer from: 182075

Part a) the equation of parabola is: (y-3)^2 = 4(x-3)

Part b) the equation of parabola is: (y+1)^2 = -12 (x-5)

Step-by-step explanation:

Part a: focus at (4, 3), and directrix x = 2

Step 1: Find the horizontal or vertical direction

As the directrix x=2 is horizontal, we will use the equation of horizontal parabola i.e.

(y-k)^2 = 4p (x-h)

Step 2: Find the vertex (h,k)

The vertex (h,k) is between the directrix and the focus

x-coordinate (h) can be found by:

$h=\frac{x-coordinate of focus + directrix}{2}\\h= \frac{4+2}{2}\\h=\frac{6}{2}\\h=3$

the value y-coordinate (k) will be the same as the y-coordinate of focus i.e. k=3

so, vertex(h,k) =(3,3)

Step 3: Find the distance from focus to vertex

The distance from focus to vertex is denoted by p

and can be found by:

p= x-coordinate of focus-x-coordinate of vertex

p= 4 - 3

p= 1

Step 4: Putting values of vertex (h,k) and p in the equation.

(y-k)^2 = 4p (x-h)

(y-3)^2 = 4(1) (x-3)

(y-3)^2 = 4 (x-3)

so, the equation of parabola is: (y-3)^2 = 4(x-3)

Part b: focus at (2, -1), and directrix x = 8

Step 1: Find the horizontal or vertical direction

As the directrix x=8 is horizontal, we will use the equation of horizontal parabola i.e.

(y-k)^2 = 4p (x-h)

Step 2: Find the vertex (h,k)

The vertex (h,k) is between the directrix and the focus

x-coordinate (h) can be found by:

$h=\frac{x-coordinate of focus + directrix}{2}\\h= \frac{2+8}{2}\\h=\frac{10}{2}\\h=5$

the value y-coordinate (k) will be the same as the y-coordinate of focus i.e. k=-1

so, vertex(h,k) =(5,-1)

Step 3: Find the distance from focus to vertex

The distance from focus to vertex is denoted by p

and can be found by:

p= x-coordinate of focus-x-coordinate of vertex

p= 2 - 5

p= -3

Step 4: Putting values of vertex (h,k) and p in the equation.

(y-k)^2 = 4p (x-h)

(y-(-1))^2 = 4(-3) (x-5)

(y+1)^2 = -12 (x-5)

So the equation of parabola is: (y+1)^2 = -12 (x-5)

Answer from: Joejar63

Part a) the equation of parabola is: (y-3)^2 = 4(x-3)

Part b) the equation of parabola is: (y+1)^2 = -12 (x-5)

Step-by-step explanation:

Part a: focus at (4, 3), and directrix x = 2

Step 1: Find the horizontal or vertical direction

As the directrix x=2 is horizontal, we will use the equation of horizontal parabola i.e.

(y-k)^2 = 4p (x-h)

Step 2: Find the vertex (h,k)

The vertex (h,k) is between the directrix and the focus

x-coordinate (h) can be found by:

$h=\frac{x-coordinate of focus + directrix}{2}\\h= \frac{4+2}{2}\\h=\frac{6}{2}\\h=3$

the value y-coordinate (k) will be the same as the y-coordinate of focus i.e. k=3

so, vertex(h,k) =(3,3)

Step 3: Find the distance from focus to vertex

The distance from focus to vertex is denoted by p

and can be found by:

p= x-coordinate of focus-x-coordinate of vertex

p= 4 - 3

p= 1

Step 4: Putting values of vertex (h,k) and p in the equation.

(y-k)^2 = 4p (x-h)

(y-3)^2 = 4(1) (x-3)

(y-3)^2 = 4 (x-3)

so, the equation of parabola is: (y-3)^2 = 4(x-3)

Part b: focus at (2, -1), and directrix x = 8

Step 1: Find the horizontal or vertical direction

As the directrix x=8 is horizontal, we will use the equation of horizontal parabola i.e.

(y-k)^2 = 4p (x-h)

Step 2: Find the vertex (h,k)

The vertex (h,k) is between the directrix and the focus

x-coordinate (h) can be found by:

$h=\frac{x-coordinate of focus + directrix}{2}\\h= \frac{2+8}{2}\\h=\frac{10}{2}\\h=5$

the value y-coordinate (k) will be the same as the y-coordinate of focus i.e. k=-1

so, vertex(h,k) =(5,-1)

Step 3: Find the distance from focus to vertex

The distance from focus to vertex is denoted by p

and can be found by:

p= x-coordinate of focus-x-coordinate of vertex

p= 2 - 5

p= -3

Step 4: Putting values of vertex (h,k) and p in the equation.

(y-k)^2 = 4p (x-h)

(y-(-1))^2 = 4(-3) (x-5)

(y+1)^2 = -12 (x-5)

So the equation of parabola is: (y+1)^2 = -12 (x-5)

Answer from: Quest

The answer of the above question is

Answer from: Quest

The answer is 109 times per second

Another question on Mathematics

Mathematics, 21.06.2019 16:40

Which of the following is most likely the next step in the series? a3z, b6y, c9x, d12w, е15v, f18u

Answers: 2

Answer

Mathematics, 21.06.2019 17:00

Ataxi company charges $2.25 for the first mile and then $0.20 per mile for each additional mile, or f = $2.25 + $0.20(m - 1) where f is the fare and m is the number of miles. if juan's taxi fare was $6.05, how many miles did he travel in the taxi? if juan's taxi fare was 7.65, how many miles did he travel in taxi

Answers: 1

Answer

Mathematics, 21.06.2019 18:40

Ineed with number 6 , explain how to get 1978

Answers: 3

Answer

Mathematics, 21.06.2019 20:00

Find the slope of the line passing through a pair of points

Answers: 2

Answer

You know the right answer?

to practice writing the equations of horizontal parabolas, write the equations of these two parabola...