Mathematics, 10.01.2020 01:31 vbucks72

The figure is made up of a rectangle and parallelogram. what is the area of this figure ?
do not round any side lengths.

The figure is made up of a rectangle and parallelogram. what is the area of this figure ? do

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Answer from: dale87

26 square units

Step-by-step explanation:

Let's label the vertices of our figure first:

A = (-10, 2)

B = (-4, 2)

C = (-2, -4)

D = (1, -3)

E = (-1, 3)

F = (-7, 3)

We are drawing the line segment AE to divide our figure in parallelogram ABEF and rectangle BCDE.

The are of the figure will be the area of parallelogram ABEF plus the area of rectangle BCDE.

To find the area of ABEF, we are using the formula for the area of a parallelogram:

A=bh

Where

is the area

is the base

is the height

The base of our parallelogram is the side AB. remember that the height of a parallelogram is the distance between two opposite sides; the sides of our parallelogram are AB and DF, so its height is h=3-2=1 . Now to find the length of the base, we are using the distance formula:

distance formula:

$d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}$

where

(x_1,y_1) are the coordinates of the first point

(x_2,y_2) are the coordinates of the second point

Replacing values

$d=\sqrt{[-4-(-10)]^{2} +(2-2)^{2}}$

$d=\sqrt{(-4+10)^{2} +(0)^{2}}[/tex[tex]d=\sqrt{(-6)^2}$

$d=\sqrt{36}$

d=6

We now have all we need to find the area of ABEF:

A=bh

A=(6)(1)

A=6 square units

Now, to the find the area of BCDE, we are using the formula for the area of a rectangle:

A=wl

where

is the area

is the width

is the length

The width of BCDE is BE and its length is BC. Using the distance formula again:

- For BE

$d=\sqrt{[-1-(-4)]^{2} +(3-2)^{2}}$

$d=\sqrt{(-1+4)^{2} +(1)^{2}}$

$d=\sqrt{(3)^{2} +1}$

$d=\sqrt{9 +1}$

$d=\sqrt{10}$

- For BC

$d=\sqrt{[-2-(-4)]^{2} +(-4-2)^{2}}$

$d=\sqrt{(-2+4)^{2} +(-6)^{2}}$

$d=\sqrt{(2)^{2}+36}$

$d=\sqrt{4+36}$

$d=\sqrt{40}$

$d=2\sqrt{10}$

We now have all we need to find the area of BCDE:

A=wl

$A=(\sqrt{10} )(2\sqrt{10} )$

$A=2(\sqrt{10})^2$

A=2(10)

square units.

All we have left is add the areas of ABEF and BCDE:

Area of the figure = ABEF + BCDE

Area of the figure = 6 + 20

Area of the figure = 26 square units

The figure is made up of a rectangle and parallelogram. what is the area of this figure ? do not r

Answer from: Quest

what graph

step-by-step explanation:

Answer from: Quest

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)

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