Hijk is a trapezoid with h(5, 4), i(10, -2), j(-8, -2), and k(-3, 4). find the coordinates of the image of h under the translation vector 〈10, -11〉.
h'(20,-13)
h'(15,-7)
h'(-5,15)
h'(7,-7)

H'(15, - 7)

Step-by-step explanation:

Given the translation < 10, - 11 >

Add 10 units to the x- coordinate of H and subtract 11 units from the y- coordinate of H, that is

H(5, 4) → H'(5 + 10, 4 - 11) → H'(15, - 7)

for the points! : )

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240