What is 64x^6 + 27 written as a sum of cubes?

(4x² + 3)(16 - 12x² + 9)

Step-by-step explanation:

A sum of cubes factors as

a³ + b³ = (a + b)(a² - ab + b²)

64 = (4x²)³ ⇒ a = 4x²

27 = 3³ ⇒ b = 3

Hence

64 + 27

(4x² + 3)((4x²)² - (4x² × 3) + 3²)

= (4x² + 3)(16 - 12x² + 9)

d (5 x (-20)) * (100 x (0.7))

step-by-step explanation:

5÷1/100 * -.7 *-20

copy dot flip

5*100 * -.7 *-20

rearrange

5*-20   * 100 *-.7

-100   *-70

7000

answer: huh

step-by-step explanation: