Find an equation of the line that contains the point (2 ,5) and is perpendicular to the line y equals one half x plus 4. use zstandard followed by zsquare with a graphing calculator to verify the equation.

  y = -2(x -2) +5

Step-by-step explanation:

The slope of the given line is 1/2, so the slope of the perpendicular line will be the negative reciprocal of that: -1/(1/2) = -2.

In a version of point-slope form, the equation of the line through the given point can be written as ...

  y = m(x -h) +k . . . . . for slope m and point (h, k)

For our slope of -2 and point (2, 5), the equation is ...

  y = -2(x -2) +5

_____

Not every graphing calculator has "ZStandard" or "ZSquare".

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

right

step-by-step explanation: