What is the best approximation of the projection of (5, -1) onto (2, 6)

0.1(2, 6) = (0.2, 0.6)

Step-by-step explanation:

The projection of B onto A will be ...

|B|·cos(θ)×uA

where uA = A/|A|, a unit vector in the A direction.

The dot product of A and B is ...

A•B = |A|·|B|·cos(θ), so the desired vector is ...

projection of B onto A = (A•B)/|A|·(A/|A|) = A·(A•B)/|A|²

For A = (2,6) and B = (5, -1), this is ...

projection of (5, -1) onto (2, 6) = (2, 6)·(2·5-6·1)/(2²+6²) = (2, 6)·4/40 = 0.1·(2, 6)

= (0.2, 0.6)

repeat the question

step-by-step explanation:

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option