Which conic section is represented by the polar equation r=3/(4+2sintheta)?
a. ellipse
b. hyperbola
c. parabola
d. circle

The conic is an ellipse  ⇒ answer A

Step-by-step explanation:

* Lets explain how to solve the problem

- The polar form equation of a conic with a focus at the origin, the

 directrix is y = ± p where p is a positive real number, and the

 eccentricity is a positive real number e is r = ep/(1 ± e sin Ф)

# If 0 ≤ e <1, then the conic is an ellipse

# If e = 1, then the conic is a parabola

# If e > 1, then the conic is an hyperbola

- Lets solve the problem

∵ The equation of the conic is r = 3/(4 + 2 sin Ф)

∵ The form of the equation is r = ep/(1 ± e sin Ф)

- We must divide up and down by 4 to make the 1st term of the

 denominator equal 1

∴ r = (3/4)/(1 + (2/4) sin Ф)

∴ ep = 3/4

∴ e = 2/4

- Lets use the rules above to identify the type of the conic

∵ e = 2/4 = 1/2

∴ 0 ≤ e < 1

∴ The conic is an ellipse

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!