Which statement about g(x)=x^2-576 is true
a. the zeros, -288 and 288, can be found when 0=(x+288)(x-288.
b. the only zero,288 , can be found when 0=(x-288)^2.
c. the zeros, -24 and 24, can be found when 0= (x+24)(x-24).
d. the only zero, 24, can be found when 0=(x-24)^2

Option C.

The zeros, -24 and 24, can be found when 0= (x+24)(x-24).

Step-by-step explanation:

we have

we know that

To find the zeros, equate the equation to zero

square root both sides

therefore

the final function for the graph becomes x-2=-1. before graphing you solve the equation, where x=1. then graph accordingly.   ( on the x-axis, 1 on the line will possess a vertical line.)

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.