Select all that apply. if 2x^2-6x=0 then

Since part of the question is not given, i assume u wanna find the possible values of x. If so, the answers are 0 and 3.

Step-by-step explanation:

2x^2 - 6x = 0

Note that 2 is a common factor. Since 0/2 = 0, we can divide both sides by 2.

Then,

x^2 - 3x    = 0

We take the common factor, aka x out.

Then we get,

x(x-3)  = 0

So one of x or x-3 has to equal 0.

If x -3 = 0, x is 3, and if x is 0, x is obviously = 0.

So x could be 3 or 0.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: