Limx-> (1+(1/x))^× using l'hospital

The limit is (famously) by definition, but if you want to compute it via L'Hopital's rule:

where . As , the numerator approaches and the denominator approaches 0. Applying L'Hopital's rule gives

The remaining approaches 1, so the original limit is , as expected.

step-by-step explanation:

answers available in this download

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