Which is the destructive interference formula for diffraction grating problems?

dsin 0 = [n+1/2]
dcos 0 = [n+1/2]
dcos 0 = n
dsin 0 = n

The formula for the brighter patches resulting from constructive interference and darker patches resulting from destructive interference in a diffraction grating is:

dsin(θ) = nλ

Here, d is the spacing between the grating, θ is the angle of light, n is the fringe order and λ is the wavelength. N has integer values only.

Destructive interference occurs between the fringes, so the formula for destructive interference becomes:

dsin(θ) = (n+1/2)λ, where n is again an integer.

point a is the center of this circle.

the ratio of the lengths of (ef/bc) and (ad/ih) is 2: 1.

step-by-step explanation:

huh? im pretty sure it is in 199

step-by-step explanation: