What is the amplitude and period of f(t)= -cos 3t?

option c

amplitude 1 ; period 2π/3

Step-by-step explanation:

Given in the question a function,

f(t)=-cos3t

Standard form of cosine function is

f(t)=acos(bt)

Amplitude is given by = |a|

Period of function is given by = 2π/b

So the amplitude is |-1| = 1

    the period is 2π/3 = 2π/3

c. The amplitude is 1.

The period is

Step-by-step explanation:

The given cosine function is ;

This function is of the form;

The amplitude is given by |a|

|-1|=1

The period of this function is given by;

The amplitude is 1.

The period is

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: