I'm stuck on this

(02.01 hc)
quadrilateral abcd is located at a(−2, 2), b(−2, 4), c(2, 4), and d(2, 2). the quadrilateral is then transformed using the rule (x − 2, y + 8) to form the image a'b'c'd'. what are the new coordinates of a', b', c', and d'? describe what characteristics you would find if the corresponding vertices were connected with line segments. (10 points)

A'(-4 , 10)

B'(-4, 12)

C'(0, 12)

D'(0, 10)

Step-by-step explanation:

Given in the question are 4 coordinates of Quadrilateral ABCD

A(−2, 2)

B(−2, 4)

C(2, 4)

D(2, 2)

The rule is (x − 2, y + 8), that means

the translation is 2 units to the left and 8 units up

Applying the rule of the translation

Step1

A(-2, 2) = A'(-2-2 , 2+8) = A'(-4 , 10)

Step 2

B(−2, 4) = B'(-2-2 , 4+8) = B'(-4, 12)

Step 3

C(2, 4) = C'(2-2 , 4+8) = C'(0, 12)

Step 4

D(2, 2) =  D'(2-2 , 2+8) = D'(0, 10)

Describe what characteristics you would find if the corresponding vertices were connected with line segments.

If point A was connected to point A', point B was connected to point B',point C was connected to point C', point D was connected to point D' then all of these line will be parallel to each other, since they were all transformed by the same amount (x-2, y+8).

step-by-step explanation:

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.