Arectangle has a perimeter of 30 feet and an area of 50 square feet. what are the dimensions of the rectangle.

I believe the shorter sides are 5 feet and the longer ones are 10. This is because when you add up the two shorter sides as 10, and the other two as 20, then add them up to 30. That's the perimeter. For the area, you would do 10•5 to get 50 for the area

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

4

step-by-step explanation: