Me with these two questions, 10 points for each so in total

2- which is an equation of the line containing the points (4,6) and (6,10) in standard form?

a: -2x+y = -8

b: -2-y = -22

c: -2+y= -2

d: 2x-y= -2

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4- which shows the equation of the line containing the point (-2,6) and having a slope of 3 in-intercept form?

a: 3y=x+20

b: y=3x-20

c: y=3x+12

d: y= -3/2x+3

Step-by-step explanation:

Q2:

The point-slope form of an equation of a line:

m - slope

The formula of a slope:

We have the points (4, 6) and (6, 10). Substitute:

          use distributive property

     add 6 to both sides

         subteact 2 from both sides

Q4:

The slope-intercept form of an equation of a line:

m - slope

b - y-intercept

Put the slope m = 3 and the coordinateso f the point (-2, 6) to the point-slope form of an equation of a line:

        use distributive property

    add 6 to both sides

look in attachments

step-by-step explanation:

a = (-2, 0)

b= (-4, 0)

c = (-5,2)

d = (-1,2)