Aright rectangular prism has a langht of 5cm, a with of 4 cm, and a hight of 3 cm. the dimensions of the prism are doubled. what is the surface area of the enlarged prism?

Given

Dimentions of the rectangular prism are

Step-by-step explanation:l=5cm, b=4cm, h=3cm

If each dimension is doubled then new prism dimensions are

L=10cm, B=8cm, H=6cm

Therefore Required surface area

Total surface area(TSA) =2(LB+BH+LH)

=2[10×8+8×6+10×6]

=2(80+48+60)

=2×188

=376square cm

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.