If f(x)=4x+2 and g(x)=x^2-6,find(f+g)(x)

(f+g)(x) = x^2 + 4x - 4

Step-by-step explanation:

f(x)=4x+2 and g(x)=x^2-6

(f+g)(x) = 4x + 2 + x^2 - 6

(f+g)(x) = x^2 + 4x - 4

Hope that helps

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!