What is the solution to the system of equations?

2x+3y=−11y=x−2
y=x−2

a) −1, −3)

b) (−1, 3)

c) (511, −311)

d) (−1, −1)

(-1, -3)

Step-by-step explanation:

I have taken the liberty of rewriting your post:  

2x+3y=−11y=x−2

y=x−2

as:

2x+3y= −11

y=x−2

In the first equation, substitute x - 2 for y, obtaining:

2x + 3(x - 2) = -11

Performing the indicated multiplication yields:

2x + 3x - 6 = -11

Combining like terms yields:

5x = -5

Solving for x:  x = -5/5 = -1

Knowing that x = 1, we can now find y from the second equation:

y = (-1) - 2 = -3

Then the solution is (-1, -3).

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.