What is the smallest number of chickens that can walk in this formation: two chickens in front of a chicken; two chickens behind a chicken, and a chicken between two chickens?

smallest number of chickens= 3

Step-by-step explanation:

In this question the given formation is:

two chickens in front of a chicken

the total number of chickens are 3

two chickens behind a chicken

the total number of chickens are 3

a chicken between two chickens

the total number of chickens are 3

So, the smallest number of chicken that can be required to make this formation will be 3.

So, if we consider that the chickens are walking in a straight line, two (2nd and 3rd) chickens will be behind the 1st chicken, two chickens( 1st and 2nd) will be in front of the last (3rd) chicken and one (2nd) chicken is in the middle of two (between 1st and 3rd) chicken.

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!