C. The second equation in system B is ย
.The solution to system B will be the same as the solution to system A.
Step-by-step explanation:
Given ย
System A:
![5x-y=-11](/tpl/images/0294/5694/7c4ee.png)
![3x-2y=-8](/tpl/images/0294/5694/58caa.png)
System B:
![5x-y=-11](/tpl/images/0294/5694/7c4ee.png)
When we multiply I equation of system A by -2 then we get new equation
( III equation )
Adding equation II ย of system A and eqaution III then we get
![-7x=14](/tpl/images/0294/5694/6da9d.png)
Hence, II equation of system B
![-7x=14](/tpl/images/0294/5694/6da9d.png)
By division property of equality
![x=\frac{14}{-7}](/tpl/images/0294/5694/25e03.png)
x=-2
Substitute the value of x=-2 in equation I of system B then we get
![5(-2)-y=-11](/tpl/images/0294/5694/676b1.png)
-10-y=-11
By simplification
=-1
y=1
By simplification
Therefore, the solution of system B is (-2,1).
Hence, option C is correct .
C. The second equation in system B is -7x=14 . The solution to system B will be the same as the solution to system A.