Will mark brainliest and 50 points.

suppose that a roof is built so that the angle at the peak and the lengths of the sides, which differ, are known. how would the width of the house be determined?

Using the Law of Cosines.  

As with many math problems, there are a number of ways this problem can be worked. Perhaps the most straightforward is to use the Law of Cosines to compute the side (c) opposite the given angle (C), given the sides (a, b) adjacent to that angle.

c² = a² + b² -2ab·cos(C)

Then the desired width of the house is ...

c = √(c²)

got a 100% on EDGE2022

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )