Which triangle has an area of 22.5 square units? circle all that apply

The triangles in figures A , D have an area of 22.5 units²

Step-by-step explanation:

* Lets explain how to solve the problem

- The area of any triangle is A = 1/2 bh , where b is the base of the

  triangle and h is the height of this base

- The horizontal line has same y-coordinates of its endpoints

- The vertical line has same x-coordinates of its endpoints

- In the Cartesian coordinates the length of any horizontal line is the

 difference between the x-coordinates of its endpoints and the length

 of any vertical line is the difference between the y-coordinates of

 its endpoints

* Lets solve the problem

# Figure A

∵ The vertices of the triangles are (-5 , 0) , (10 , 0) , (-1 , 3)

∵ the end points of its base are (-5 , 0) , (10 , 0)

∵ The base of the triangle = 10 - (-5) = 10 + 5 = 15 units

∵ The height of the triangle is the difference between the

   y-coordinates of its vertex and the y-coordinate of its base

∵ The y-coordinate of the vertex is 3

∵ The y-coordinate of the base is 0

∴ The height of the triangle = 3 - 0 = 3 units

∴ Its A = 1/2 (15)(3) = 22.5 units²

* The triangle in figure A has an area of 22.5 units²

# Figure B

∵ The vertices of the triangles are (-1 , -1) , (-6 , -1) , (-2 , -8)

∵ the end points of its base are (-1 , -1) , (-6 , -1)

∵ The base of the triangle = -1 - (-6) = -1 + 6 = 5 units

∵ The height of the triangle is the difference between the

   y-coordinates of its vertex and the y-coordinate of its base

∵ The y-coordinate of the vertex is -8

∵ The y-coordinate of the base is -1

∴ The height of the triangle = -1 - (-8) = -1 + 8 = 7 units

∴ Its A = 1/2 (5)(7) = 17.5 units²

* The triangle in figure B has an area of 17.5 units²

# Figure C

∵ The vertices of the triangles are (-9 , 2) , (-1 , 2) , (-7 , 8)

∵ the end points of its base are (-9 , 2) , (-1 , 2)

∵ The base of the triangle = -1 - (-9) = -1 + 9 = 8 units

∵ The height of the triangle is the difference between the

   y-coordinates of its vertex and the y-coordinate of its base

∵ The y-coordinate of the vertex is 8

∵ The y-coordinate of the base is 2

∴ The height of the triangle = 8 - 2 = 6 units

∴ Its A = 1/2 (8)(6) = 24 units²

* The triangle in figure C has an area of 24 units²

# Figure D

∵ The vertices of the triangles are (0 , 0) , (0 , -9) , (5 , -7)

∵ the end points of its base are (0 , 0) , (0 , -9)

∵ The base of the triangle = 0 - (-9) = 0 + 9 = 9 units

∵ The height of the triangle is the difference between the

   x-coordinates of its vertex and the x-coordinate of its base

∵ The x-coordinate of the vertex is 5

∵ The x-coordinate of the base is 0

∴ The height of the triangle = 5 - 0 = 5 units

∴ Its A = 1/2 (5)(9) = 22.5 units²

* The triangle in figure D has an area of 22.5 units²

∴ The triangles in A , D have an area of 22.5 units²

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine