In circle k , diameter cd is drawn and point e is located on the circle such that ce=16 and de=30 .what is the length of the radius of circle k?

The length of the radius of the circle K is

Step-by-step explanation:

we know that

The triangle CDE is a right triangle with the 90 degree angle at point E

so

Applying the Pythagoras Theorem

Find the length of CD (diameter of the circle K)

substitute the values

Find the radius

Remember that the radius is half the diameter

so

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this