Given: ab tangent to circle o at b, and secant through point a intersect the circle at points c and d. find cd, if
ab = 4 cm, ac = 2 cm;

CD = 6 cm.

Step-by-step explanation:

In the figure attached AB is the tangent of circle O at point B. A secant through point A intersect the circle at C and D.

mAB = 4cm and  mAC = 2cm

We have find the length of CD.

By the theorem of secant and tangent

AB² = AC×AD

Here AC = 2 cm

and AD = AC + CD = (2 + CD)

Now we replace the values in the formula

4² = 2(2 + CD)

16 = 4 + 2.CD

2.CD = 16 - 4 = 12

Therefore CD = 6 cm is the answer.

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step-by-step explanation:

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