Sixty nine percent of u. s households play video or computer games. chose 4 heads of households at random. find the probability that none play video/computer games?

0.00923521

Step-by-step explanation:

Given : The probability U.S households play video or computer games=69%=0.69

here, the probability of each U.S household play video or computer games is fixed as 0.69

Then, the probability of each U.S household not play video or computer games= 1-0.69=0.31

For independent events the probability of their intersection is product of probability of each event.

Now, the probability that none play video/computer games will be :-

y=mx+

srry idk

step-by-step explanation: