An suv is traveling at a speed of 18 m/s. if the sub has a mass of 1,550 kg, what force must be applied to stop it in 8 seconds?

First we have to find for the acceleration with the equation (Vo -V1)/t

Given: V1 = 18 m/s
Vo = 0 m/s
t=8

(0-18m/s)/8 = -2.25m/s^2

Then we compute for the Force. F=ma

F=1550*-2.25m/s^2

F= -3487.5 N

Thus, the answer is -3487.5 N 

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