Is it possible to draw a rectangle that has an area of 24 square units and a perimeter of 24 units? explain

No for whole number dimensions

Step-by-step explanation:

The area of a rectangle is found using the formula A = l*w. This means for an area of 24 square units the dimensions must be two factors of 24. The factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24. Using each pair of factors, find if any would have a perimeter of 24 too.

1 and 24 has perimeter 50

2 and 12 has perimeter 28

3 and 8 has perimeter 22

4 and 6 has perimeter 20

It is not possible to draw a rectangle with whole number dimensions which will have area and perimeter 24.

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2