You have a cone with a radius of 8 ft and a height of 10 ft. find the area of the triangle formed by a perpendicular cross-section through the cone’s center.

80ft²

Step-by-step explanation:

Given in the question,

radius of cone's base = 8ft

              cone's base = base of triangle

height of cone = 10 ft

height of cone = height of triangle

Area = 1/2(h)(b)

here h = height of triangle

        b = base of triangle

A = 1/2(8)(10)

A = 40ft²

Since the section is 2 similar triangles back to back around the vertical centre so the area cross sectional area of triangle form in the cone is 2(40)ft² = 80ft²

lo.lll

step-by-step explanation:

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3