To the nearest tenth of a cubic inch, how much volume is added to a spherical ballon whose radius grows from 10 to 20 inches long?
a) 8245.7 in^3
b) 17367.6 in^3
c) 29321.5 in^3
d) 41225.4 in^3

C) 29321.5 in^3

Step-by-step explanation:

We find the volumes of the two spheres and then we find the difference.

radius = 10 inches

V = (4/3)(pi)r^3

V = (4/3)(3.14159)(10 in)^3

V = 4188.8 in^3

radius = 20 inches

V = (4/3)(pi)r^3

V = (4/3)(3.14159)(20 in)^3

V = 33510.3 in^3

The difference in volumes is:

33510.3 in^3 - 4188.8 in^3 = 29321.5 in^3

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.