Use the distance formula to find base and height of the triangle with points (-3, 4), (1, 4), (1, 1) show your work.

The base = 4 units and the height = 3 units

Step-by-step explanation:

* Lets remember the rule of the distance between 2 points

- The two points are (x1 , y1) and (x2 , y2)

∴ The distance = √[(x2 - x1)²+(y2 - y1)²]

* The vertices of the triangles are (-3 , 4) , (1 , 4) , (1 , 1)

- If two points have the same y-coordinate

∴ The line joining the to point is horizontal

∴ Its length = x2 - x1

- Because √[(x2 - x1)²+(y2 - y1)²] and y2 = y1

∴ d = √(x2 - x1)² ⇒ cancel power 2 with the radical sign

∴ d = x2 - x1

* Similar you can find the vertical distance

- If two points have the same x-coordinate

∴ The line joining the to point is vertical

- Its length = y2 - y1

∵ The points (-3 , 4) , (1 , 4) have same y-coordinate

∴ This side of the triangle is horizontal

∴ Its length = 1 - -3 = 4

∵ The points (1 , 4) , (1 , 1) have same x-coordinate

∴ This side of the triangle is vertical line

∴ Its length = 4 - 1 = 3

* The two sides of the triangle are ⊥

∴ One of them is the base of the triangle and the other is the height

* The base = 4 units and the height = 3 units

step-by-step explanation:

two pairs of adjacent sides are of equal length. this implies that one diagonal divides the kite into congruent triangles, and so the angles between the two pairs of equal sides are equal in measure. it also implies that the diagonals are perpendicular.