Choose the equation and the slope of the line that passes through (5,-3) and is perpendicular to the x-axis.

The equation is x = 5 ⇒ F

The slope is undefined ⇒ C

Step-by-step explanation:

* Lets talk about the slopes of the line and the relation between

 the parallel lines and the perpendicular lines

- If the two lines are parallel, then their slopes are equal

- If the two lines perpendicular, then the product of their slopes = -1

 that meas one of them is additive inverse and multiplicative

 inverse of the other

- If the line parallel to x-axis, then all the points on that line

 have the same y-coordinates (a , b) (horizontal line)

∵ The slope = (y2 - y1)/(x2 - x1)

∴ Its slope = 0 because (y2 - y1) = 0

* Its equation is y = b

- If the line parallel to y-axis, then all the points on that line

 have the same x-coordinates (a , b) (vertical line)

∵ The slope = (y2 - y1)/(x2 - x1)

∴ Its slope = undefined because (x2 - x1) = 0

* Its equation is x = a

* Now look to the problem

- The line is ⊥ x-axis means it is parallel to y-axis (vertical line)

∴ Its slope = undefined

∵ It passes through point (5 , -3)

∴ Its equation is x = 5

* The equation is x = 5

* The slope is undefined

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.