Which statement best describes the equation x5 + x3 – 14 = 0?

a. the equation is quadratic in form because it is a fifth-degree polynomial.

b. the equation is quadratic in form because the difference of the exponent of the lead term and the exponent of the middle term is 2.

c. the equation is not quadratic in form because it cannot be rewritten as a second-degree polynomial.

d. the equation is not quadratic in form because the exponent of the lead term is not the square of the exponent of the middle term.

It should be C.

cause you could multiply x a lot and that's a huge stretch so it wouldn't really work which makes it a straight line which also makes a linear equation so you could rewrite it as a quadratic but not really no its not a quadratic

C

Step-by-step explanation:

The equation x5 + x3 – 14 = 0 is a polynomial with three terms. This polynomial has as its highest exponent a 5 making it a 5th degree polynomial. This is not quadratic because a quadratic has as its highest exponent a 2 making it a second degree polynomial. Because the exponent of the leading term is 5, this cannot be written as a polynomial with degree 2. THe best answer choice which matches this analysis is C.

e.

step-by-step explanation:

because there are always 10 numbers in a phone number.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.