Mathematics, 03.02.2020 11:44 patriciaceaser2980

Instructions: drag the tiles to the correct boxes to complete the pairs. not all tiles will be used.

match each linear equation with its slope and a point on the line.

tiles:

slope= 3, point= (2,17)

slope= 1/3, point= (19,2)

slope= 3, point= (5,2)

slope= 1/3, point= (17,-2)

slope= 1/3, point= (-5,2)

pairs:

y=3x-13

y=3x+11

3y=x+11

3y=x-13

Answers: 1

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Answers

Answer from: lanipooh01

y = 3x - 13slope= 3, point= (5,2)

y = 3x + 11slope= 3, point= (2,17)

3y = x + 11slope= 1/3, point= (-5,2)

3y = x - 13slope= 1/3, point= (19,2)

Step-by-step explanation:

To match each equation to its slope and point, remember that an equation in y = mx + b has slope m. The point must also satisfy or make true the equation when substituted for (x,y).

y=3x-13 has slope 3. The point (2,17) make it false. But (5,2) makes it true.

17 = 3(2) - 13 2 = 3(5) - 13

17 = 6-13 2 = 15 - 13

17 = - 7 False 2 = 2 True

y=3x+11 has slope 3. This means (2,17) must be true.

3y=x+11 can be converted to y = 1/3x + 11/3. It has slope 1/3. Test each point.

2= 1/3(19) + 11/3 -2 = 1/3(17) + 11/3 2 = 1/3(-5) + 11/3

2 = 19/3 + 11/3 -2 = 17/3 + 11/3 2 = -5/3 + 11/3

False False 2 = 6/3 True

3y=x-13 can be converted to y = 1/3x - 13/3. It has slope 1/3. Test each remaining point.

2= 1/3(19) - 13/3 -2 = 1/3(17) - 13/3

2 = 19/3 - 13/3 -2 = 17/3 - 13/3

2 = 6/3 -2 = 4/3

True False

Answer from: mxxrrr

y=3x-13 : slope = 3, point = (5, 2)

y=3x+11 : slope = 1/3, point = (-5, 2)

3y=x+11 : slope = 3, point = (2,17)

3y=x-13 : slope = 1/3, point = (19, 2)

Step-by-step explanation:

Since, the equation of a line passes through (x_1, y_1) with slope m is,

y-y_1=m(x-x_1)

If m = 3, x_1=2 , y_1=17

Equation of the line,

y-17=3(x-2)

y-17=3x-6

$y = 3x - 6 + 17\implies y = 3x + 11$

If m = 1/3, x_1=19 , y_1=2

Equation of the line,

$y-2=\frac{1}{3}(x-19)$

3y-6=x-19

$3y = x-19+6\implies 3y = x -13$

If m = 3, x_1=5 , y_1=2

Equation of the line,

y-2=3(x-5)

y-2=3x-15

$y = 3x - 15 + 2\implies y = 3x -13$

If m = 1/3, x_1=17 , y_1=-2

Equation of the line,

$y+2=\frac{1}{3}(x-17)$

3y+6=x-17

$3y=x-17-6\implies 3y = x-23$

If m = 1/3, x_1=-5 , y_1=2

Equation of the line,

$y-2=\frac{1}{3}(x+5)$

3y-6=x+5

$3y=x+5+6\implies 3y = x+11$

Answer from: Quest

Bis your answer. it only holds the decimal numerals
Which of the following is not a possible value for a probability?

Answer from: Quest

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

$\begin{bmatrix}1 & 0 & 0& |5 \\ 0& 2& 0& |8\\ 0& 0& 3& |9\end{bmatrix}$

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,

$\begin{bmatrix}1 & 0 & 0& |5 \\ 0& 1& 0& |4\\0& 0& 1& |3\end{bmatrix}$

What is the next step in solving this augmented matrix using gauss-jordan elimination method

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