What is the vertex of the quadratic function f(x)=(x-8)(x-2)

Vertex (5 ,-9)

Step-by-step explanation:

Given : Function f(x) = (x – 8)(x – 2).

To find : What is the vertex of the quadratic function .

Solution : We have given that f(x) = (x – 8)(x – 2).

On removing parenthesis

f(x) = x²-2x -8x +16.

f(x) = x²-10x +16.

We need to find vertex of this function ,

Vertex: (h, k)

h = -.

Plugging values

h = -.

h = 5 this is the x- coordinate,

Now , we will plug x= 5 in quadratic function .

k  = (5)²-10(5)+16.

k = 25-50 + 16

k= -9.

Vertex (5 ,-9)

Therefore, Vertex (5 ,-9).

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hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6