Ajar contains balls numbered 1 to 10. two balls are drawn with replacement. what is the probability that both balls are numbered 2 or less?

Step-by-step explanation:

The number of ways that you can draw 2 balls without restriction is 10 * 10 = 100

Two balls will give you 2 or less (meaning 1) or 2*2 = 4

Four ways are possible

2  and 2

2 and 1

1 and 2

1 and 1

4/100 = 1/25 is the probability of making this happen.

there is no grid

step-by-step explanation:

i think the amount would be $140.62