What is the range of the function f(x) = 1/3e^x - 2/3 + 1/2?

(1/2, ∞ ).  This corresponds to Answer B

Step-by-step explanation:

Important:  enclose that negative exponent (-2/3) inside parentheses:

1/3e^(x- 2/3) + 1/2

and also that coefficient, 1/3:

(1/3)e^(x- 2/3) + 1/2

The range of the exponential function y = e^x is (0, ∞ ); that is, y is always positive, never zero or negative.  

The function of that "1/2" is to shift the entire graph 1/2 unit up.

Thus, the range   (0, ∞ )  becomes  (1/2, ∞ ).  This corresponds to Answer B.

how many players are there?

step-by-step explanation: