(β800)+(β200)+(β50)+(β12.5)+
Mathematics, 01.11.2019 14:31 skywil8981
What is the sum of the first eight terms of the series?
(β800)+(β200)+(β50)+(β12.5)+
round the answer to two decimal places.
β1066.68
β1066.65
β1066.60
β1062.50
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What is the sum of the first eight terms of the series?
(β800)+(β200)+(β50)+(β12.5)+
(β800)+(β200)+(β50)+(β12.5)+
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