There are 5 players in a baseball lineup. how many different batting orders are possible for these 5 players? (use factorials to find the probability of the number of permutations)

5! or 120.

Step-by-step explanation:

Think about this logically:

You have 5 players to start off with, so you have 5 players that can go in the first position.

That leaves you with 4 players. Any one of those 4 players can go in the second position.

And then there were 3 players. Any one of those 3 players can go in the third position.

2 to go! Pick your favorite player out of the 2 available to go in the fourth position.

And that leaves just one player who has to go last.

This can be modeled as: 5x4x3x2x1, or 5!, which equals 120 unique permutations.

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation: