Find the mean median and interquartile range for the data set below 17,23,8,5,9,16,22,11,13,15,17,18

Mean- 14.5

Median- 15.5

Interquartile Range- 7.5

Step-by-step explanation:

Let's order the numbers first. 5, 8, 9, 11, 13, 15, 16, 17 , 17, 18, 22, 23.

Just by looking at it and counting up to the middle, we can find that the middle two numbers are 15 and 16. Average them by adding them up and dividing by two to get the median, 15.5

Next, find the mean. By adding up all the numbers we find that the sum of this data set is 174. Divide that by the amount of numbers there are (12) to get that the mean is 14.5

Last part is the interquartile range, to do this, we have to split up the data set into two parts.

5, 8, 9, 11, 13, 15   |   16, 17, 17, 18, 22, 23

Find the median of the left side by averaging 9 and 11 to get 10. Do the same for the right side with 17 and 18 and you'll find that the median of the right side is 17.5. Now that we have both the 1st and 3rd quartile, subtract the 1st quartile from the 3rd quartile to find the interquartile range, which is 7.5.

or

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)