Which polynomial function has a leading coefficient of 1 and roots 2i and 3i with multiplicity 1?
f(x) = (x – 2i)(x – 3i)
f(x) = (x + 2i)(x + 3i)
f(x) = (x – 2)(x – 3)(x – 2i)(x – 3i)
f(x) = (x + 2i)(x + 3i)(x – 2i)(x – 3i)

f(x) = (x – 2i)(x – 3i)

Step-by-step explanation:

The above funtion gives us roots

x - 2i = 0 , x - 3i = 0

x = 2i , x = 3i

Both the roots have multiplicity 1.

And for leading coefficient, there will be only one variable having power 2 which is x^2 and the coefficient is 1 so the first function fulfills all conditions.

d

step-by-step explanation:

in a an geometric explicit equation, the first number is the starting rate. in this case 10.

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: