Identify the graph of 4x^2+5y^2=20 for t(5,-6) and write an equation of the translated or rotated graph in general form..

The answer is ellipse of equation 4x² + 5y² - 40x + 60y + 260 = 0 ⇒ answer (b)

Step-by-step explanation:

* At first lets talk about the general form of the conic equation

- Ax² + Bxy + Cy²  + Dx + Ey + F = 0

∵ B² - 4AC < 0 , if a conic exists, it will be either a circle or an ellipse.

∵ B² - 4AC = 0 , if a conic exists, it will be a parabola.

∵ B² - 4AC > 0 , if a conic exists, it will be a hyperbola.

* Now we will study our equation:

* 4x² + 5y² = 20

∵ A = 4 , B = 0 , C = 5

∴ B² - 4 AC = (0)² - 4(4)(5) = -80

∴ B² - 4AC < 0

∴ The graph is ellipse or circle

* If A and C are nonzero, have the same sign, and are not

 equal to each other, then the graph is an ellipse.

* If A and C are equal and nonzero and have the same

 sign, then the graph is a circle.

∵ A and C have same signs with different values

∴ It is an ellipse

* Now lets study T(5 , -6), that means the graph will translate

 5 units to the right and 6 units down

∴ x will be (x - 5) and y will be (y - -6) = (y + 6)

* Lets substitute the x by ( x - 5) and y by (y + 6) in the equation

∴ 4(x - 5)² + 5(y + 6)² = 20

* Use the foil method

∴ 4(x² - 10x + 25) + 5(y² + 12y + 36) = 20

* Open the brackets

∴ 4x² - 40x + 100 + 5y² + 60y + 180 = 20

* Collect the like terms

∴ 4x² + 5y² - 40x + 60y + 280 = 20

∴ 4x² + 5y² - 40x + 60y + 280 - 20 = 0

∴ 4x² + 5y² - 40x + 60y + 260 = 0

* The answer is ellipse of equation 4x² + 5y² - 40x + 60y + 260 = 0

3

step-by-step explanation:

because where the point where the 2 lines intersect is (3,-1) the x value is 3