For which distributions is the median the best measure of center? select each correct answer.

Answer with explanation:

Let me start answering this Question like this.

Why Median came into existence because Mean was not good enough to provide better solution to Statistical Data Set.

What, is Median.Median of a discrete data set ,is Middle value in the data set when arranged in ascending or descending order.Suppose you have to find whether wages of Employee in certain Organization is appropriate or not.You will use two measure of variation for that Purpose: 1. Mean 2.Median

Consider Bar graph of Data set 1

Variate in set builder form ={10,15,20,25,30,35,30,25,20,15,10}

When arranged in ascending order ={10,10,15,15,20,20,25,25,30,30,35}=11(Odd)

Mean

Median =Mid value =20

Median  - Smallest variate =20 -10=10

Largest Variate - Median =35-20=15

→→→Consider Bar Graph of Data set 2

Variate in set builder form ={22,18,20,26,30,28,20,9,9,5,4,3,3,2}

When arranged in ascending order ={2,3,3,4,5,9,9,18,20,20,22,26,28,30}=14(Even)

Mean

Median

Median  - Smallest variate =13.5 - 2=11.5

Largest Variate - Median =30 -13.5=16.5

→→Consider Bar Graph of Data set 3

Variate in set builder form ={4,3,4,,4,5,5,5,4,5,5}

When arranged in ascending order ={3,4,4,4,4,5,5,5,5,5}=10(Even)

Mean

Median

Median  - Smallest variate =4.5 -3=1.5

Largest Variate - Median =5-4.5=0.5

Consider Bar graph of Data set 4

Variate in set builder form ={11,12,13,14,15,18,19,24,28,15,12,11}

When arranged in ascending order ={11,11,12,12,13,14,15,15,18,19,24,28}=12(even)

Mean

Median

Median  - Smallest variate =14.5 - 11=3.5

Largest Variate - Median =28 - 14.5=13.5

Drawing Box plot of four data set

Found that, for data set 3, median lies in the center.

Option 2 and Option 3

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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