What value of c would make the equation x^2 +8x+c=0

Answer

Step 1: Add -x^2 to both sides.

x2+c+8x+−x2=0+−x2

c+8x=−x2

Step 2: Add -8x to both sides.

c+8x+−8x=−x2+−8x

c=−x2−8x

c=−x2−8x

I hope is is the answer you are looking for

4th option is correct xy=-10

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