Question part points submissions used use newton's method with the specified initial approximation x1 to find x3, the third approximation to the root of the given equation. (round your answer to four decimal places.) 2x3 − 3x2 + 2 = 0, x1 = −1

Set . Find the tangent line to at the point when :

(slope of )

Set , the root of . The tangent line to at has slope and thus equation

which has its root at .

(The actual value of this root is about -0.6777)

the range is 19

step-by-step explanation:

the range is biggest number minus the smallest, so in this case it would be

41 - 22 = 19

5050

hope this !